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A reaction has a rate constant of 1.23×10⁻⁴ s⁻¹ at 27 °C and 0.233 s⁻¹ at 77 °C.

Determine the activation barrier for the reaction.

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Final answer:

The question involves using the Arrhenius equation to calculate activation energy and frequency factor for reactions with known rate constants at different temperatures.

Step-by-step explanation:

The question asked is related to the determination of the activation energy and the frequency factor for chemical reactions, using the Arrhenius equation. The Arrhenius equation links the rate constant, k, the activation energy, Ea, and the temperature, T, via the formula k = A exp(-Ea/(RT)), where A is the pre-exponential factor or frequency factor, R is the gas constant, and T is the temperature in Kelvin.

To calculate these constants, temperature must be converted from Celsius to Kelvin, and then the formula can be re-arranged to allow the calculation of activation energy using the known values of the rate constants at different temperatures. This involves logarithmic manipulation of the equation to isolate the Ea term. Once Ea is determined, it can be used along with one of the provided rate constants to solve for the frequency factor, A.

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