Question

To what volume should you dilute 125 mL of an 8.10 M CuCl₂ solution so that 52.0 mL of the diluted solution contains 4.83 g CuCl₂?

a. 1470 mL
b) 785 mL
c) 975 mL
d) 1050 mL

Answer 1

To dilute the 8.10 M CuCl₂ solution, you should add enough water to obtain a volume of 1050 mL.

Step-by-step explanation:

To dilute the CuCl₂ solution, we can use the dilution equation:

C₁V₁ = C₂V₂

where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume.

First, calculate the number of moles of CuCl₂ in the diluted solution using the given mass and molar mass of CuCl₂:

moles = mass / molar mass

Next, rearrange the dilution equation to solve for V₂:

V₂ = (C₁V₁) / C₂

Substitute the given values into the equation:

V₂ = (8.10 M * 125 mL) / (4.83 g / 63.546 g/mol)

Solve for V₂:

V₂ = 1050 mL

Therefore, the volume to dilute 125 mL of the 8.10 M CuCl₂ solution is 1050 mL.