Final answer:
To calculate [OH-] in a solution of KOH, we need to determine the molarity of KOH. The molarity of KOH is equivalent to the concentration of hydroxide ions ([OH-]). To find the molarity of KOH, we can convert the density of the solution to mass and then to moles.
Step-by-step explanation:
To calculate [OH-] in a solution of KOH, we need to determine the concentration of hydroxide ions. In this case, we are given the density of the solution, 6.33x10-3 g/mL. We can use this information to find the molarity of KOH. Molarity (M) is defined as moles of solute divided by volume of solution in liters.
First, we need to find the moles of KOH. Given the density of the solution, we can determine the mass of KOH in 1 mL of the solution. Then, we can convert the mass of KOH to moles using the molar mass of KOH (56.11 g/mol). Finally, we can calculate the molarity of KOH by dividing the moles of KOH by the volume of the solution in liters.
Once we have the molarity of KOH, we know that KOH is a strong base and dissociates completely in water. This means that for every KOH molecule that dissolves, it releases one hydroxide ion (OH-). Therefore, the concentration of hydroxide ions ([OH-]) is the same as the molarity of KOH.
In summary, to calculate [OH-] in the solution of KOH, we need to find the molarity of KOH by converting the density of the solution to mass and then to moles. The molarity of KOH is equivalent to the concentration of hydroxide ions ([OH-]).