Final answer:
The probability that two heterozygous lizards (Ss) will produce an offspring homozygous for no stripes (ss) is 1 out of 4, or 25%, as determined by a Punnett square calculation.
Step-by-step explanation:
The probability that two heterozygous lizards (Ss) will produce an offspring that is homozygous for no stripes (ss) can be calculated using a Punnett square, which shows the possible genotypes their offspring can have. Since both parents are Ss, each can produce two types of gametes: S or s. When we fill out the Punnett square, we see four possible combinations: SS, Ss, sS, and ss. Out of these, only one is the desired homozygous recessive genotype (ss).
Therefore, the probability of two Ss lizards producing an ss offspring is 1 out of 4, or 25%. This is because there is one ss combination out of the four possible genotype combinations in the Punnett square.