Question

What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to

raise the temperature from 22ᵒC to 33.6ᵒC?

Answer 1

≈ 395,8 J/(kg * °C)

Step-by-step explanation:

m = 44 g = 0,044 kg

`t_(1)` = 22 °C

`t_(2)` = 33,6 °C

Q = 202 J

The formula is: Q = c * m * (
`t_(2) - t_(1)`)

c =
`(Q)/(m * (t_(2) - t_(1) ))`

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)