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What mass of HI should be present in 0.200 L of solution to obtain a solution with each of the following pH's? pH= 1.20

a) 0.010 g
b) 0.025 g
c) 0.050 g
d) 0.100 g

User Vim
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1 Answer

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Final answer:

To obtain a solution with a pH of 1.20, 1.6146 grams of HI are required in 0.200 L of solution. The provided answer options do not match the calculated mass.

Step-by-step explanation:

To determine what mass of HI is needed to obtain a solution with a pH of 1.20 in 0.200 L of solution, we must first convert the pH into hydrogen ion concentration [H+], use the concentration to find the number of moles of HI, and then calculate the mass from the moles.

pH is related to hydrogen ion concentration by the formula:

pH = -log[H+]

By inversely calculating the hydrogen ion concentration from the given pH, we have:

[H+] = 10-pH = 10-1.20 = 0.0631 M

Now, we can find the moles of HI in 0.200 L of solution:

moles HI = volume (L) × molarity (M) = 0.200 L × 0.0631 M = 0.01262 moles

Hydroiodic acid (HI) has a molar mass of approximately 127.91 g/mol, thus:

mass HI = moles × molar mass = 0.01262 moles × 127.91 g/mol = 1.6146 g

None of the given mass options (a) 0.010 g, (b) 0.025 g, (c) 0.050 g, or (d) 0.100 g correspond to the calculated mass of 1.6146 g necessary for a pH of 1.20.

User Murat Yasar
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