Final answer:
To calculate the concentration of [OH-] in a solution, you can use the formula [OH-] = 10^-14 / [H3O+].
To determine the concentration of hydroxide ions ([OH-]), one can use the relationship that the product of [H3O+] and [OH-] in water at 25 °C is a constant 1.0×10⁻¹⁴. Calculations are made for specific values of [H3O+], and [OH-] is found accordingly for each given scenario.
Step-by-step explanation:
In order to calculate the concentration of [OH-] in a solution using the given [H3O+] concentration, you can use the formula:
[OH-] = 10-14 / [H3O+]
For example, if [H3O+] = 2.0 x 10-6 M, then:
[OH-] = 10-14 / (2.0 x 10-6)
Simplifying the calculation, you get [OH-] = 5 x 10-9 M.
Therefore, the concentration of [OH-] in the solution is 5 x 10-9 M.
To determine the concentration of hydroxide ions ([OH-]), one can use the relationship that the product of [H3O+] and [OH-] in water at 25 °C is a constant 1.0×10⁻¹⁴. Calculations are made for specific values of [H3O+], and [OH-] is found accordingly for each given scenario.
To calculate the concentration of hydroxide ions ([OH-]) in a solution, we can use the following information:
The product of the hydronium ion concentration ([H3O+]) and the hydroxide ion concentration ([OH-]) in an aqueous solution at 25 °C is always 1.0×10⁻¹⁴.
For the given values of [H3O+], we can calculate [OH-] using the formula [H3O+] × [OH-] = 1.0×10⁻¹⁴.
Calculations:
- [OH-] when [H3O+] = 2.0 x 10⁻⁶
[OH-] = 1.0×10⁻¹⁴ / [H3O+]
[OH-] = 1.0×10⁻¹⁴ / (2.0 x 10⁻⁶)
[OH-] = 5.0 x 10⁻⁹ M - When [H3O+] = 100 x [OH-], rearranging and solving gives us:
[OH-] = 1.0×10⁻¹⁴ / (100 x [OH-])
After solving we get:
[OH-] = 1.0 x 10⁻⁷ M - If [H3O+] = [OH-], then:
[OH-] = [H3O+] = √(1.0 x 10⁻¹⁴) = 1.0 x 10⁻⁷ M