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Write an equation of the line that passes through (-2,-7) and is perpendicular to the line y = -x + 7

User Milson
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Final answer:

The equation of the line that passes through (-2, -7) and is perpendicular to y = -x + 7 is y = x - 5.

Step-by-step explanation:

To find the equation of a line that is perpendicular to y = -x + 7 and passes through (-2, -7), we first need to determine the slope of the given line. The equation y = -x + 7 is in the form y = mx + b, where m is the slope. In this case, the slope is -1.

The slope of a line perpendicular to this is the negative reciprocal of -1, which is 1.

Next, we'll use the slope and the point (-2, -7) to find the equation of the perpendicular line using the point-slope form. The formula is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

Plugging in the values:

y - (-7) = 1(x - (-2))

y + 7 = x + 2

y = x - 5

Therefore, the equation of the line that passes through (-2, -7) and is perpendicular to y = -x + 7 is y = x - 5.

User Badjr
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