Final answer:
The given set of numbers represents even numbers; hence, the answer is (c) Even numbers. The sample space consists of whole numbers starting at one and less than 20, and the probability of selecting an even number (Event A) is 9/19. Event A AND B, which includes numbers that are both even and greater than 13, has a probability of 3/19.
Step-by-step explanation:
When considering the set of numbers {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}, each number is an even number. Therefore, the answer is (c) Even numbers.
Using the Provided Sample Space
The sample space S is given by: S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}.
Let event A be the set of even numbers (A = {2, 4, 6, 8, 10, 12, 14, 16, 18}), and event B be the set of numbers greater than 13 (B = {14, 15, 16, 17, 18, 19}).
The probability of event A occurring (P(A)) is the number of outcomes in A (9) divided by the number of outcomes in S (19), which is 9/19.
The set A AND B contains all outcomes that are both even and greater than 13, so A AND B = {14, 16, 18}. The probability of A AND B occurring (P(A AND B)) is the number of outcomes in A AND B (3) divided by the number of outcomes in S (19), which is 3/19.