Final answer:
The statement is false because in digital circuits, 0 and 1 represent two distinct voltage levels, not the presence or absence of an electronic charge.
Step-by-step explanation:
The statement that in a bit, 0 is used to represent the electronic state of off (presence of an electronic charge) and 1 is used to represent the electronic state of on (absence of an electronic charge) is false. In digital circuits, which are the building blocks of modern computer systems, the binary digits 0 and 1 represent two distinct voltage levels, with 0 typically representing a lower voltage (often close to zero volts) and 1 representing a higher voltage (such as +5 volts or +3.3 volts), depending on the specific technology used.
For example, in Transistor-Transistor Logic (TTL), which is a class of digital circuits, a low voltage of about 0 volts represents a 0 (off) state, and a higher voltage of about +5 volts represents a 1 (on) state. These binary values are not related to the presence or absence of an electronic charge, but rather to the voltage levels which transistors within an integrated circuit can recognize and interpret as binary information.
In quantum computing, however, the binary system is expanded into quantum bits or qubits where different rules apply, but these are beyond the scope of traditional digital circuits and not related to the initial statement.