Question

If a 6.7 g ring is heated using 30.0 calories, its temperature rises 20°C. Calculate the specific heat capacity of the ring?

Answer 1

The specific heat capacity of the ring is calculated by using the formula q = mcΔT and the given values: q = 30.0 calories, m = 6.7 grams, and ΔT = 20°C, resulting in a specific heat capacity of 0.224 cal/g°C.

Step-by-step explanation:

To calculate the specific heat capacity of the ring, we use the formula:

q = mcΔT

Where q is the heat energy in calories, m is the mass in grams, ΔT is the change in temperature in degrees Celsius, and c is the specific heat capacity in calories/g°C. We rearrange the formula to solve for c:

c = q / (mΔT)

The problem gives us:

• q = 30.0 calories
• m = 6.7 grams
• ΔT = 20°C

Plugging these values into the equation, we get:

c = 30.0 cal / (6.7 g × 20°C)

c = 30.0 cal / (134 g°C)

c = 0.224 cal/g°C

Therefore, the specific heat capacity of the ring is 0.224 cal/g°C.