Answer:
A
Explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
(h, k) are the coordinates of the vertex and a is a multiplier
Given
f(x) = - 2x² - 12x - 16
To complete the square the coefficient of the x² term must be 1
Factor out - 2 from - 2x² - 12x
f(x) = - 2(x² + 6x) - 16
add/ subtract ( half the coefficient of the x- term )² to x² + 6x
f(x) = - 2(x² + 2(3)x + 9 - 9 ) - 16
= - 2(x + 3)² + 18 - 16
= - 2(x + 3)² + 2 ; y = 2