In triangle ABC with sides AB, BC, and CA measuring 4, 5, and 3 units, respectively, tan(theta) is found to be 4/3 using the formula tan(theta) = perpendicular/base.
We are given that in triangle ABC where side AB is 4 which is perpendicular BC is 5 which is hypotenuse and CA is 3 which is base .
Now , we know that tan ( theta) = perpendicular / base
From the given figure we can see that perpendicular is AB and base is AC which measure 4 and 3 respectively.
So , by substituting the values we can find the value of tan(theta)
tan(theta) = perpendicular / base
tan(theta) = 4 / 3
So , the value of tan(theta) is equal to 4/3.
The probable question may be:
In triangle ABC where side AB is 4 which is perpendicular BC is 5 which is hypotenuse and CA is 3 which is base .