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A 13-foot ladder leans against the side of a building, forming an angle A with the ground. Given that the foot of the ladder is being pulled away from the building at the rate of 0.1 feet per second, what is the rate of change of 0 when the top of the ladder is 12 feet above the ground?

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Final answer:

The rate of change of angle A when the top of the ladder is 12 feet above the ground is -0.0083 feet per second.

Step-by-step explanation:

To find the rate of change of angle A when the top of the ladder is 12 feet above the ground, we can use the concept of similar triangles. Let x be the distance between the foot of the ladder and the wall.

Since the ladder is leaning against the wall, we have a right triangle formed by the ladder, the ground, and the wall.

The length of the ladder is given as 13 feet and the distance x is changing at a rate of 0.1 feet per second.

Using the Pythagorean theorem, we can express the relation between the height h and the distance x as:

h^2 = 13^2 - x^2

Differentiating both sides of this equation with respect to time, we get:

2h * (dh/dt) = -2x * (dx/dt)

Substituting the given values, we have:

2 * 12 * (dh/dt) = -2 * x * 0.1

Simplifying this equation, we get:

24 * (dh/dt) = -0.2x

Now we need to find the value of x when the top of the ladder is 12 feet above the ground. Using the Pythagorean theorem, we have:

12^2 = 13^2 - x^2

Simplifying this equation, we get:

x^2 = 169 - 144

x^2 = 25

x = 5 feet

Now we can substitute the value of x into the equation we derived earlier:

24 * (dh/dt) = -0.2 * 5

Simplifying this equation, we get:

dh/dt = -0.2/24

dh/dt = -0.0083 feet per second

Therefore, the rate of change of angle A when the top of the ladder is 12 feet above the ground is -0.0083 feet per second.

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