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In the normalization process, if you find that every determinant in a relation is a candidate key then you have determined that:

a. The relation is not in 1NF
b. The relation is in 2NF
c. The relation is in 3NF
d. The relation is in BCNF

User Opedge
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Final answer:

In the database normalization process, if every determinant in a relation is a candidate key then the relation is in Boyce-Codd Normal Form (BCNF). BCNF is a higher normalization form that removes redundancies due to functional dependence, being a stricter version of 3NF.

Step-by-step explanation:

When working with database normalization, if every determinant in a relation is a candidate key, we have determined that the relation is in Boyce-Codd Normal Form (BCNF). This level of normalization addresses redundancy due to functional dependence. A relation is in BCNF if and only if, for every one of its non-trivial functional dependencies, X -> Y, X is a superkey.

To provide more context, the normalization process involves the application of rules to remove redundancies and dependencies in a database. The Boyce-Codd Normal Form is a stricter version of the Third Normal Form (3NF). For a relation to be in 2NF, it must be in 1NF and it must not have any partial dependency of a non-prime attribute (an attribute that is not a part of any candidate key) on a proper subset of any candidate key. A relation is said to be in 3NF if it is in 2NF and all the attributes that are not part of a candidate key are non-transitively dependent on every candidate key.

User Jalperin
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