Final answer:
4.13 moles of SO3 will be produced from 6.2 moles of O2 and excess sulfur according to the stoichiometry of the provided chemical reaction.
Step-by-step explanation:
The student is asking about a stoichiometry problem, which is a part of chemistry. Specifically, this is a stoichiometric calculation to determine the amount of sulfur trioxide (SO3) produced in a chemical reaction given the number of moles of oxygen (O2) when sulfur (S) is in excess.
According to the balanced chemical equation:
2S(s) + 3O2(g) → 2SO3(g)
We see that it takes 3 moles of O2 to produce 2 moles of SO3. So with 6.2 moles of O2 present, we can calculate the moles of SO3 produced as follows:
− First, determine the mole ratio from the equation, which is 2 moles of SO3 per 3 moles of O2.
− Then, using this ratio: (6.2 moles O2) × (2 moles SO3/3 moles O2) = 4.13 moles of SO3
Therefore, 4.13 moles of SO3 will be produced from 6.2 moles of O2 and excess S.