54.1k views
0 votes
For the reaction

2S(s) + 3O2(g)
2SO3(g)

how many moles of SO3 will be produced from 6.2 mol O2 and excess S?

User Neutreno
by
8.0k points

1 Answer

3 votes

Final answer:

4.13 moles of SO3 will be produced from 6.2 moles of O2 and excess sulfur according to the stoichiometry of the provided chemical reaction.

Step-by-step explanation:

The student is asking about a stoichiometry problem, which is a part of chemistry. Specifically, this is a stoichiometric calculation to determine the amount of sulfur trioxide (SO3) produced in a chemical reaction given the number of moles of oxygen (O2) when sulfur (S) is in excess.

According to the balanced chemical equation:

2S(s) + 3O2(g) → 2SO3(g)

We see that it takes 3 moles of O2 to produce 2 moles of SO3. So with 6.2 moles of O2 present, we can calculate the moles of SO3 produced as follows:

− First, determine the mole ratio from the equation, which is 2 moles of SO3 per 3 moles of O2.
− Then, using this ratio: (6.2 moles O2) × (2 moles SO3/3 moles O2) = 4.13 moles of SO3

Therefore, 4.13 moles of SO3 will be produced from 6.2 moles of O2 and excess S.

User Ted Xu
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.