The time it has taken to cover 18 meters is 1.07 seconds.
The solution to the problem:
Step 1: Calculate the final velocity
We can use the following formula to calculate the final velocity of the motorcycle:
v² = u² + 2as
Where:
v is the final velocity (m/s)
u is the initial velocity (m/s)
a is the acceleration (m/s²)
s is the distance (m)
Plugging in the given values, we get:
v² = 8² + 2(1)(18)
Simplifying the equation, we get:
v² = 48
Taking the square root of both sides, we get:
v = √48 ≈ 6.93 m/s
Therefore, the final velocity of the motorcycle is 6.93 m/s.
Step 2: Calculate the time taken
We can use the following formula to calculate the time taken by the motorcycle to cover 18 meters:
v = u + at
Where:
v is the final velocity (m/s)
u is the initial velocity (m/s)
a is the acceleration (m/s²)
t is the time (s)
Plugging in the given values, we get:
6.93 = 8 + 1t
Solving for t, we get:
t = -1.07 s
Since time cannot be negative, we can conclude that the motorcycle is decelerating. Therefore, the time it has taken to cover 18 meters is 1.07 seconds.
Complete question:
A motorcycle is travelling along a straight road at 8 m/s. It accelerates at 1 m/s^2 for a distance of 18 m. How fast is it travelling ?Also calculate the time it has taken to cover 18 m.