Final answer:
The chloride ion concentration in the 2.00-liter solution containing 7.00 moles of CaCl₂ is between 6.5 M and 7.5 M.
Step-by-step explanation:
The chloride ion concentration can be determined by analyzing the number of moles of CaCl₂ in the solution. Since each molecule of CaCl₂ dissociates into two chloride ions, the concentration of chloride ions will be twice the concentration of CaCl₂.
In this case, the solution contains 7.00 moles of CaCl₂ in a 2.00-liter solution. So the concentration of chloride ions is 2 * (7.00 mol / 2.00 L) = 7.00 M.
Therefore, the chloride ion concentration is between 6.5 M and 7.5 M.