Final answer:
The point-slope form of the equation of a line perpendicular to y = 7/4x and passing through (-3, 2) is y - 2 = -4/7(x + 3).
Step-by-step explanation:
The point-slope form of a linear equation is given by y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
In this case, we are given the point (-3, 2) and are asked to find the equation of a line perpendicular to y = 7/4x passing through this point.
The slope of the given line is 7/4, so the slope of the perpendicular line will be the negative reciprocal, which is -4/7.
Using the point-slope form, we have the equation y - 2 = -4/7(x + 3).