Final answer:
The sulfur in S₂O₃²⁻ could be reduced to H₂S in a certain chemical reaction, as H₂S represents a lower oxidation state of sulfur which is typical for such reductions d)H2S.
Step-by-step explanation:
In the question, you are asking about the reduction of the sulfur in S₂O₃²⁻ to another sulfur-containing compound. Reduction involves a decrease in oxidation number, meaning electrons are gained by the sulfur atom. Given the compounds listed, H₂S is a likely product of the reduction of S₂O₃²⁻.
This conclusion is supported by references which mention that the sulfur in H₂S is in a lower oxidation state compared to other sulfur compounds such as SO₃²⁻ or SO₄²⁻, and thus H₂S is a commonly reduced form of sulfur in chemical reactions.