Question

Write a balanced molecular and net ionic equation for:

Fe(s) + CuSO₄(aq)
Options:
A. Fe(s) + CuSO₄ (aq) → Cu(s) + Fe₂(SO₄)₃ (aq)
B. Cu(s) + Fe₂(SO₄)₃ (aq) → Fe(s) + CuSO₄ (aq)
C. Fe(s) + CuSO₄ (aq) → Cu(s) + FeSO₄ (aq)
D. Cu(s) + FeSO₄ (aq) → Fe(s) + CuSO₄ (aq)

Answer 1

The balanced molecular equation between Fe(s) and CuSO4(aq) is Fe(s) + CuSO4(aq) → Cu(s) + FeSO4(aq), and the corresponding net ionic equation is Fe(s) + Cu^2+(aq) → Cu(s) + Fe^2+(aq).

Step-by-step explanation:

The correct option for the balanced molecular and net ionic equation for the reaction between iron (Fe) and copper(II) sulfate (CuSO4) is option C. The balanced molecular equation is:

Fe(s) + CuSO4 (aq) → Cu(s) + FeSO4 (aq)

To write the net ionic equation, we only include the species that undergo a change during the reaction. In this case, iron metal (Fe) is oxidized to iron(II) ions (Fe2+) and copper(II) ions (Cu2+) are reduced to copper metal (Cu). The spectator ions, in this case sulfate (SO42- ), do not participate in the reaction directly and are not included in the net ionic equation. Therefore, the net ionic equation is:

Fe(s) + Cu2+ (aq) → Cu(s) + Fe2+ (aq)