Question

What is the molarity of sulfuric acid if 12.88 mL is neutralized completely by 26.04 mL of 0.1024 M NaOH?

a) 0.205 M
b) 0.410 M
c) 0.308 M
d) 0.154 M

Answer 1

To find the molarity of sulfuric acid, calculate the moles of NaOH, use the balanced equation to determine the moles of sulfuric acid, and divide by the volume of sulfuric acid. The molarity is 0.104 M.

Step-by-step explanation:

To find the molarity of sulfuric acid, we first need to calculate the number of moles of NaOH using the given concentration and volume. Then, using the balanced equation, we can determine the number of moles of sulfuric acid. Finally, we divide the moles of sulfuric acid by the volume of sulfuric acid in liters to get the molarity.

Step 1: Calculate moles of NaOH - 0.02604 L x 0.1024 mol/L = 0.00267 mol NaOH

Step 2: Use balanced equation - 1 mol H₂SO4 reacts with 2 mol NaOH, so 0.00267 mol NaOH corresponds to 0.00134 mol H₂SO4.

Step 3: Calculate molarity of sulfuric acid - Molarity = 0.00134 mol H₂SO4 / 0.01288 L = 0.104 M