Final answer:
The concentration of Na+ ions in a solution varies according to the number of Na+ ions that each compound provides upon dissociation; therefore, the options provided in the question do not correctly represent the concentrations of Na+ for the given solutions. 2.0 M Na2SO4 provides 4.0 M Na+, 3.5 M NaCl provides 3.5 M Na+, and 1.5 M Na3PO4 provides 4.5 M Na+ B) 3.5 M Nacl.
Step-by-step explanation:
The question asks about the concentration of sodium ions (Na+) in different sodium compound solutions. In each case, the concentration of Na+ will depend on the number of sodium ions that result from the dissociation of the compound in water.
- A. 2.0 M Na2SO4: Sodium sulfate will dissociate into 2 moles of Na+ for every mole of Na2SO4. Hence, the Na+ concentration will be 2 x 2.0 M = 4.0 M.
- B. 3.5 M NaCl: Sodium chloride will dissociate into 1 mole of Na+ for every mole of NaCl. Therefore, the Na+ concentration remains 3.5 M.
- C. 1.5 M Na3PO4: Sodium phosphate will dissociate into 3 moles of Na+ for every mole of Na3PO4. So, the Na+ concentration will be 3 x 1.5 M = 4.5 M.
Therefore, the correct option for concentrations of Na+ ions is not listed in your provided options. The correct concentrations should be 4.0 M for Na2SO4, 3.5 M for NaCl, and 4.5 M for Na3PO4.