Question

Complete the following reactions with balanced molecular and net ionic equations-

1. KCl(aq) + Pb(NO₃)₂(aq)
a) KCl(aq)+Pb(NO₃)₂(aq)→KNO₃(aq)+PbCl₂(s)
b) KCl(aq)+Pb(NO₃)₂(aq)→KNO₃(aq)+PbCl₂(aq)
c) KCl(aq)+Pb(NO₃)₂(aq)→KCl(aq)+Pb(NO₃)₂(s)
d) KCl(aq)+Pb(NO₃)₂(aq)→KNO₃(aq)+PbCl₂(aq)

Answer 1

The correct balanced molecular equation for the reaction between KCl and Pb(NO₃)² is Pb(NO₃)²(aq) + 2 KCl(aq) → 2 KNO₃(aq) + PbCl₂(s), and the net ionic equation is Pb²⁺(aq) + 2 Cl−(aq) → PbCl₂(s).

Step-by-step explanation:

When Potassium Chloride (KCl) reacts with Lead(II) Nitrate [Pb(NO₃)²], a double displacement reaction occurs. The correct balanced molecular equation for the reaction is:

Pb(NO₃)²(aq) + 2 KCl(aq) → 2 KNO₃(aq) + PbCl₂(s)

And the net ionic equation:

Pb²⁺(aq) + 2 Cl⁻(aq) → PbCl₂(s)

In this reaction, solid Lead(II) Chloride (PbCl₂) precipitates out of the solution, while Potassium Nitrate (KNO₃) remains in aqueous form. It should be noted that Potassium Nitrate does not precipitate, and Lead(II) Chloride is insoluble in water, hence forms a precipitate.