Question

Soluble vs. Insoluble:

AgNO₃
KOH
Mg₂(PO₄)₂
Fe(OH)2
(NH₄)2CO₃
Zn(C₂H₃O₂)₂
CuS
a) Soluble: 1, 2, 5; Insoluble: 3, 4, 6, 7
b) Soluble: 1, 2, 5, 6; Insoluble: 3, 4, 7
c) Soluble: 1, 2, 5, 6, 7; Insoluble: 3, 4
d) Soluble: 1, 2, 5, 7; Insoluble: 3, 4, 6

Answer 1

Using solubility rules, compounds AgNO3, KOH, and (NH4)2CO3 are soluble, while Mg2(PO4)2, Fe(OH)2, and CuS are insoluble. Zn(C2H3O2)2 is also soluble.Soluble: 1, 2, 5, 6; Insoluble: 3, 4, 7

Step-by-step explanation:

To classify each compound as soluble or insoluble, we can use established solubility rules:

1. All nitrates (NO3) are soluble.
2. Salts formed with group 1 cations (such as Na+, K+, etc.) and NH4+ are soluble.
3. Acetates (C2H3O2) and most sulfates (SO42-) are soluble, with exceptions like BaSO4, PbSO4, Ag2SO4, and SrSO4 being insoluble.
4. Most hydroxides are insoluble, except those of group 1 and some group 2 (Ca, Sr, and Ba).
5. Most phosphates (PO43-) and carbonates (CO32-) are insoluble.
6. Most sulfides are insoluble, especially those of transition metals.

Using these rules, we can classify the compounds as follows:

• AgNO3 (silver nitrate) is soluble due to rule 1.
• KOH (potassium hydroxide) is soluble because KOH is a group 1 hydroxide (rule 4).
• Mg2(PO4)2 (magnesium phosphate) is insoluble due to rule 5.
• Fe(OH)2 (iron(II) hydroxide) is insoluble (rule 4).
• (NH4)2CO3 (ammonium carbonate) is soluble because of rule 2.
• Zn(C2H3O2)2 (zinc acetate) is soluble because acetates are soluble (rule 3).
• CuS (copper sulfide) is insoluble, as most sulfides of transition metals are (rule 7).

Therefore, the correct classification is:

Soluble: 1, 2, 5, 6; Insoluble: 3, 4, 7