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If 0.023 grams of additional HCl is added to 0.500 L of a 0.100 M HCl solution, what will happen to the molarity?

a) It will increase
b) It will decrease
c) It will not change
d) None of the above

1 Answer

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Final answer:

The molarity of a 0.500 L, 0.100 M HCl solution will increase if an additional 0.023 grams of HCl is added. Calculations include converting mass to moles, combining with the original mole amount, and dividing by volume to find the increased molarity.

Step-by-step explanation:

If 0.023 grams of additional HCl is added to 0.500 L of a 0.100 M HCl solution, the molarity will increase. To answer this question, first, calculate the number of moles of HCl added using the formula:

number of moles = mass (g) / molar mass (g/mol)

Then find the new total number of moles in solution by adding the moles of added HCl to the original 0.500 L of 0.100 M HCl (which contains 0.050 moles of HCl). Finally, calculate the new molarity (M) by dividing the total number of moles by the total volume of the solution in liters.

By following these steps:

  1. Convert the mass of HCl to moles.
  2. Add this to the original amount of moles in 0.500 L of a 0.100 M solution.
  3. Divide by the total volume to find the new molarity.

The molarity of the solution after adding 0.023 grams of HCl will indeed be higher than the original 0.100 M.

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