Question

What mass of NaOH is required to react exactly with 25.0 mL of 1.2 M HCl?

a) 1.2 g
b) 1.8 g
c) 2.4 g
d) 3.5 g

Answer 1

To find the mass of NaOH required to react with 25.0 mL of 1.2 M HCl, calculate the moles of NaOH using the mole ratio from the balanced equation and then multiply by the molar mass of NaOH.option a) 1.2 g

Step-by-step explanation:

To find the mass of NaOH required to react with 25.0 mL of 1.2 M HCl, we need to use the concept of stoichiometry. The balanced chemical equation for the reaction between NaOH and HCl is:

HCl + NaOH → NaCl + H2O

From the equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl. Therefore, we can use the mole ratio to calculate the moles of NaOH:

moles of NaOH = 1.2 M x 0.0250 L = 0.030 moles

Finally, we can calculate the mass of NaOH using its molar mass:

mass of NaOH = 0.030 moles x 40 g/mol = 1.2 g