Final answer:
The linear speed of a point on the edge of a record spinning with a 0.25-meter radius and taking 0.54 seconds to make one revolution is approximately 2.91 meters per second.
Step-by-step explanation:
The student is asking about the linear speed of a point on the edge of a record that spins on a record player. To find the linear speed, we need to use the formula v = 2πr/T, where v is the linear speed, r is the radius, and T is the period of rotation. The radius r is given as 0.25 meters, and the period T is given as 0.54 seconds.
Plugging in the values we have: v = 2π(0.25 m) / 0.54 s, which gives us the linear speed of the point on the edge of the record. By calculating, we get v ≈ 2.91 m/s.
Therefore, the speed of the record at its edge is approximately 2.91 meters per second.