Question

Base your answer to questions #5 through #7 on the diagram below which represents carts A and B being pushed apart by a spring which exerts an average force of 50. Newtons for a period of 0.20 second. [Assume friction-less conditions.]

5)
What is the average acceleration of cart B during the 0.20-second interaction?

A)
0 m/s2

B)
10. m/s2

C)
25 m/s2

D)
50. m/s2

Answer 1

The average acceleration of cart B during the 0.20-second interaction is 25 m/s². The correct option s C)

25 m/s2.

Step-by-step explanation:

The average acceleration of cart B can be calculated using the formula a = F/m, where a is the acceleration, F is the force, and m is the mass of the object. In this case, the force exerted by the spring is 50 N and the mass of cart B is the same as cart A. Therefore, the average acceleration of cart B is 50 N divided by the mass of cart B.

Since the masses of both carts are equal, the average acceleration of cart B is also equal to the average acceleration of cart A. The answer is 25 m/s² (C).