Question

A chemistry book gives the density of cork as 0.24g/cm3. A student finds the density of cork to be 0.26g/cm3. Calculate his percent error

Answer 1

The student's percent error in measuring the density of cork, which was experimentally found to be 0.26 g/cm³ compared to the accepted 0.24 g/cm³, is approximately 8.33%.

Step-by-step explanation:

The question asks how to calculate the percent error in a density measurement.

First, we identify the absolute error by subtracting the accepted value from the experimental value: 0.26 g/cm³ (experimental density) - 0.24 g/cm³ (accepted density) = 0.02 g/cm³ (absolute error).

Next, we calculate the percent error by dividing the absolute error by the accepted value and then multiplying by 100 to get a percentage:

Percent error = (Absolute error / Accepted density) × 100% = (0.02 g/cm³ / 0.24 g/cm³) × 100% ≈ 8.33%

Therefore, the student's percent error in the density measurement of cork is approximately 8.33%.