Final answer:
The traveler's speed off the walkway is 5 ft/s and the speed of the moving walkway is 3 ft/s, found by setting up a system of equations and solving them simultaneously.
Step-by-step explanation:
To solve for the traveler's speed off the walkway and the speed of the moving walkway, we need to set up a system of equations. Let's denote the traveler's speed off the walkway as x ft/s, and the speed of the walkway as y ft/s.
When the traveler is walking against the walkway, their ground speed is the difference between their walking speed and the walkway's speed. This can be represented as:
x - y = 2 (Equation 1)
When the traveler is walking with the walkway, their ground speed is the sum of their walking speed and the walkway's speed, which can be represented as:
x + y = 8 (Equation 2)
Now we can solve these two equations simultaneously:
- Add Equation 1 and Equation 2: (x - y) + (x + y) = 2 + 8, which simplifies to 2x = 10. Solving for x, we get x = 5 ft/s.
- Substitute x back into Equation 2: 5 + y = 8, solving for y, we get y = 3 ft/s.
Therefore, the traveler's speed off the walkway is 5 ft/s, and the speed of the moving walkway is 3 ft/s.