Question

Use for questions 1-4

Zn + 2HCl → ZnCl2 + H2


1) If 0.8 moles of Zn are used,
how many moles of HCl are
required?
2) If 3.5 moles of Zn are used,
how many moles of HCl are
required?
3) If 4.8 moles of HCl are used,
how many moles of H, are
produced?
4) If 0.48 moles of ZnCl, are
produced, how many moles of
HCl are needed?

Answer 1

Answer: 1) 1.6 moles of HCl

2) 7.0 moles of HCl

3) 2.4 moles of hydrogen

4) 0.96 moles of HCl

Step-by-step explanation:

The balanced chemical equation is:

`Zn+2HCl\rightarrow ZnCl_2+H_2`

According to stoichiometry :

1 mole of
`Zn` require = 2 moles of
`HCl`

0.8 moles of
`Zn` will require=
`(2)/(1)* 0.8=1.6moles` of
`HCl`

3.5 moles of
`Zn` will require=
`(2)/(1)* 3.5=7.0moles` of
`HCl`

According to stoichiometry :

2 moles of
`HCl` produce = 1 mole of
`H_2`

4.8 moles of
`HCl` will require=
`(1)/(2)* 4.8=2.4moles` of
`H_2`

According to stoichiometry :

1 mole of
`ZnCl_2` are produced by = 2 moles of
`HCl`

0.48 moles of
`ZnCl_2` are produced by =
`(2)/(1)* 0.48=0.96moles` of
`HCl`