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What is the concentration (m) of lithium ions in 4.57 l of a 1.63 m li 3p solution?

User Awea
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Final answer:

The concentration of lithium ions in the 4.57 L solution is 1.63 M

Step-by-step explanation:

The concentration of lithium ions in the solution can be calculated using the formula for molarity:

Molarity (M) = moles of solute / volume of solution (in liters)

Given that the molarity (m) of the solution is 1.63 M and the volume of the solution is 4.57 L, we can calculate the moles of solute:

Moles of solute = molarity x volume of solution

Moles of solute = 1.63 M x 4.57 L = 7.4521 mol

Finally, we can calculate the concentration of lithium ions:

Concentration (m) = moles of solute / volume of solution (in liters)

Concentration (m) = 7.4521 mol / 4.57 L = 1.63 M

User Bryce Frank
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