Final answer:
The question pertains to the reflection of light rays in a mirror and uses the law of reflection to explain the concept. Reflecting a point over a line in the context of a flat mirror results in a point that is symmetric and equidistant from the line on the opposite side, preserving object and image heights and distances.
Step-by-step explanation:
The question seems to revolve around the reflection of light rays in a mirror, and by extension, touches upon the law of reflection. A point (such as point Q) after being reflected over the line (mirror) would still be at the same distance from the line but on the opposite side.
This is principally due to the fact that the angle of incidence equals the angle of reflection, and that distances from the mirror are preserved in the case of a flat mirror.
Reflection over the Line
When a point is reflected over a line such as in the case of point Q(-3,2) reflecting over a mirror, the reflected point, Q', will be equidistant from the line but on the opposite side, creating a symmetric point. If we assume the line of reflection to be the y-axis, the reflected point would be Q'(3,2).
To understand the reflection process further, follow this example: Imagine a flat mirror and a point P in front of it. The reflected rays from P that reach an observer's eye appear to originate from a point Q behind the mirror.
If we apply the same principle for another point P' and its image Q', we see that the distance from the mirror to P (object distance do) is the same as from the mirror to Q' (image distance d1). This maintains the object height equal to the image height, with both the object and its image being upright with respect to each other.