Final answer:
To find the mass of octane required to produce 3670 kJ of heat, we can use the given information that the combustion of 1.00 L of isooctane produces 33,100 kJ of heat.
Step-by-step explanation:
To calculate the mass of octane required to produce 3670 kJ of heat, we can use the given information that the combustion of 1.00 L of isooctane produces 33,100 kJ of heat. This means that the heat produced per liter is 33100 kJ. We can set up a proportion to find the mass:
33100 kJ/1 L = 3670 kJ/x g
Cross-multiplying, we find that x = (3670 kJ * 1 L) / 33100 kJ = 0.111 L. The density of isooctane is given as 0.692 g/mL, so we can convert liters to grams:
0.111 L * 0.692 g/mL = 0.077 g.
Therefore, the mass of octane required to produce 3670 kJ of heat is 0.077 grams.