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What mass of octane (in grams) is required to produce 3670 kJ of heat?

User Minh Le
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1 Answer

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Final answer:

To find the mass of octane required to produce 3670 kJ of heat, we can use the given information that the combustion of 1.00 L of isooctane produces 33,100 kJ of heat.

Step-by-step explanation:

To calculate the mass of octane required to produce 3670 kJ of heat, we can use the given information that the combustion of 1.00 L of isooctane produces 33,100 kJ of heat. This means that the heat produced per liter is 33100 kJ. We can set up a proportion to find the mass:

33100 kJ/1 L = 3670 kJ/x g

Cross-multiplying, we find that x = (3670 kJ * 1 L) / 33100 kJ = 0.111 L. The density of isooctane is given as 0.692 g/mL, so we can convert liters to grams:

0.111 L * 0.692 g/mL = 0.077 g.

Therefore, the mass of octane required to produce 3670 kJ of heat is 0.077 grams.

User Griffins
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