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What quantity of heat (kj) will be absorbed by 49.1 g piece of aluminum (specific heat =0.930j/g c as it changes temperature from 23.0 c to 67.0 c

User Seanbun
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1 Answer

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Final answer:

To find the heat absorbed by a piece of aluminum, multiply the mass by the specific heat and the change in temperature. The 49.1 g of aluminum absorbs approximately 2.01 kJ when its temperature is raised from 23.0 C to 67.0 C.

Step-by-step explanation:

To calculate the quantity of heat absorbed by the piece of aluminum, we use the equation Q = mcΔT, where Q is the quantity of heat, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Given that the mass of the aluminum is 49.1 g, the specific heat is 0.930 J/g°C, and the change in temperature is 67.0°C - 23.0°C = 44.0°C, we can substitute these values into the equation.

Q = (49.1 g)(0.930 J/g°C)(44.0°C) = 2025 J.

User Roseann Solano
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