Question

What mass of precipitate will form if 1.50 L of a highly concentrated solution of PbClO₃ reacts to produce a precipitate?

Answer 1

To find the mass of the precipitate, calculate the moles of PbClO₃ using the concentration and volume, and then convert moles to grams using the molar mass.

Step-by-step explanation:

In the given question, we need to find the mass of precipitate that will form when 1.50 L of a highly concentrated solution of PbClO₃ reacts. To solve this, we need to calculate the number of moles of PbClO₃ using the concentration and volume of the solution.

First, we need to find the moles of PbClO₃ using the equation:

PbClO₃(aq) → PbCl₂(s) + O₂(g)

1 mol of PbClO₃ reacts to produce 1 mol of PbCl₂. So, the number of moles of PbClO₃ will be equal to the concentration of PbClO₃ multiplied by the volume in liters:

Moles of PbClO₃ = concentration of PbClO₃ × volume of solution

Finally, we can convert the moles of PbClO₃ to grams using the molar mass of PbClO₃ to find the mass of the precipitate that will form.