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What is the volume in liters of 375.0 g of krypton (kr) at standard temperature and pressure.

User XValidated
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Final answer:

To calculate the volume of krypton at standard temperature and pressure (STP), we can use the ideal gas equation.

Step-by-step explanation:

To calculate the volume of krypton (Kr) at standard temperature and pressure (STP), we can use the ideal gas equation:

V = (nRT)/P

Where:

  • V is the volume
  • n is the number of moles of gas
  • R is the gas constant
  • T is the temperature
  • P is the pressure

First, we need to convert the mass of krypton to moles using its molar mass. The molar mass of krypton is 83.80 g/mol. So, the number of moles is given by:

n = mass/molar mass = 375.0 g / 83.80 g/mol = 4.47 mol

Plugging in the values:

V = (4.47 mol x 0.08206 L atm mol-1 K-1 x 273.15 K) / 1 atm

V = 0.992 L

Therefore, the volume of 375.0 g of krypton at STP is 0.992 liters.

User Estebanpdl
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