Question

What is the specific heat of tin if a 55.0g sample absorbs 982 j of heat to raise its temperature by 85.0 °c.

Answer 1

The specific heat of tin is 0.227 J/g°C.

Step-by-step explanation:

The specific heat formula is given by
`\( q = mcΔT \)`, where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.

First, rearrange the formula to solve for specific heat:
`\( c = (q)/(mΔT) \).`

Given:

`\( q = 982 \, \text{J} \),`

`\( m = 55.0 \, \text{g} \),`

`\( ΔT = 85.0 \, \text{°C} \).`

Plug in the values:
`\( c = \frac{982 \, \text{J}}{55.0 \, \text{g} * 85.0 \, \text{°C}} \).`

Calculating:
`\( c = \frac{982 \, \text{J}}{4675 \, \text{J/°C}} = 0.227 \, \text{J/g°C} \).`

Therefore, the specific heat of tin is 0.227 J/g°C.