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What is the torque τd about axis d due to f⃗ ? (d is the point located at a distance d from the origin and making an angle ϕ with the x axis.)

User Aoles
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1 Answer

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Final answer:

The magnitude of the torque τd caused by a force vector about axis d is calculated using the formula T = rF sin θ, taking into account the distance r from the pivot point to the force application and the perpendicular lever arm r1.

Step-by-step explanation:

The torque τd about axis d due to a force f can be calculated using the relationship T = rF sin θ where T is the torque, r is the distance from the pivot point to the point where the force is applied, F is the magnitude of the force, and θ is the angle between the force and the vector directed from the point of application to the pivot point. In your case, the axis d is at a distance d from the origin and makes an angle φ with the x-axis. The perpendicular lever arm r1 is defined as r1 = r sin θ. To compute the torque, it's essential that the angle θ used in the torque equation is the angle between the force vector and the lever arm, which might differ from the angle φ given in the problem description.

User Nick Holden
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