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What is the speed of a high-speed electron traveling at right angles to a 0.80-tesla magnetic field with a force of -7.5 × 10-12 newtons? the charge of an electron is 1.60 × 10-19 c.

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Final answer:

To find the speed of the high-speed electron traveling at right angles to a 0.80-tesla magnetic field with a force of -7.5 x 10-12 newtons, you can use the formula F = qvB.

Step-by-step explanation:

To find the speed of a high-speed electron traveling at right angles to a 0.80-tesla magnetic field with a force of -7.5 × 10-12 newtons, we can use the formula for magnetic force: F = qvB. In this equation, F is the force, q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field strength.

First, rearrange the formula to solve for v: v = F / (qB). Substitute the given values into the equation: v = (-7.5 × 10-12 N) / ((1.60 × 10-19 C) × (0.80 T)). Calculate v using this equation and you will get the speed of the electron.

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