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What is the pressure of the sample of gas trapped in the open-tube mercury manometer shown below if atmospheric pressure is 736 mmhg and h = 9.2 cm? (write numeric answer)

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Final answer:

The pressure of the trapped gas sample in the open-tube mercury manometer, with an atmospheric pressure of 736 mmHg and the mercury height difference of 9.2 cm, is 644 mmHg after converting the height to mm and subtracting it from the atmospheric pressure.

Step-by-step explanation:

To determine the pressure of the sample of gas trapped in the open-tube mercury manometer, if atmospheric pressure is 736 mmHg and h is 9.2 cm, we need to convert the height h from centimeters to millimeters by multiplying by 10 (since 1 cm = 10 mm), making h equal to 92 mm. To calculate the pressure of the trapped gas (Pgas), we subtract the height h from the atmospheric pressure. Thus, Pgas = Atmospheric pressure - h, which is Pgas = 736 mmHg - 92 mmHg = 644 mmHg.

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