Question

What is the percent yield of NH₃ if a reaction starts with 77.0 g CaCN₂ and produces 27.1 g NH₃? CaCN₂ + 3H₂O ⟶ CaCO₃ + 2NH₃

Answer 1

The percent yield of NH₃ is 62.9%

Step-by-step explanation:

To find the percent yield, we need to compare the actual yield (27.1 g NH₃) to the theoretical yield. In the balanced equation, the stoichiometric ratio between CaCN₂ and NH₃ is 1:2. This means that for every 1 mole of CaCN₂, we should produce 2 moles of NH₃.

First, calculate the theoretical yield of NH₃ using the molar mass of CaCN₂:

• 77.0 g CaCN₂ * (1 mol CaCN₂ / 80.1 g CaCN₂) * (2 mol NH₃ / 1 mol CaCN₂) * (17.03 g NH₃ / 1 mol NH₃) = 43.14 g NH₃

Then, calculate the percent yield:

• Percent yield = (27.1 g NH₃ / 43.14 g NH₃) * 100% = 62.9%