Final answer:
The mole fraction of 58 g of KF dissolved in 180 g of water is 1/11.
Step-by-step explanation:
To calculate the mole fraction, we need to first calculate the moles of KF and water. Mole = mass / molar mass. The molar mass of KF is 58 g/mol. So, moles of KF = 58 g / 58 g/mol = 1 mol. The molar mass of water is 18 g/mol. So, moles of water = 180 g / 18 g/mol = 10 mol.
The mole fraction of KF in the solution is the moles of KF divided by the total moles of solute and solvent. Mole fraction = moles of KF / (moles of KF + moles of water) = 1 mol / (1 mol + 10 mol) = 1/11.