Final answer:
The de Broglie wavelength of an electron moving at 10% of the speed of light is calculated to be 2.42×10-12 m, which does not match any of the options provided in the question.
Step-by-step explanation:
The de Broglie wavelength (λ) of a particle is given by the formula λ = h / p, where h is Planck's constant (6.626×10-34 m2kg/s) and p is the momentum of the particle. For an electron with a mass (M) of 9.11×10-31 kg moving at 10% of the speed of light (c), its momentum (p) would be its mass times its velocity (v), i.e. p = M × v. Given that the speed of light c is approximately 3.00×108 m/s, 10% of this speed is 3.00×107 m/s. Inserting the values, we get λ = (6.626×10-34 m2kg/s) / (9.11×10-31 kg × 3.00×107 m/s), which calculates to λ = 2.42×10-12 m. Therefore, none of the provided options (a, b, c, or d) are correct.