Question

The flywheel of a motor has a mass of 300 kg and a moment of inertia of 580 kg⋅m². The motor develops a constant torque of 2000 N⋅m, and the flywheel starts from rest. What is the angular acceleration of the flywheel?

A) 3.45 rad/s²
B) 6.90 rad/s²
C) 9.81 rad/s²
D) 12.34 rad/s²

Answer 1

Using the formula α = T/I, the angular acceleration of the flywheel with a moment of inertia of 580 kg⋅m² and subjected to a torque of 2000 N⋅m is 3.45 rad/s².

Step-by-step explanation:

The question asks us to determine the angular acceleration of the flywheel of a motor with a mass of 300 kg and a moment of inertia of 580 kg⋅m². The motor develops a constant torque of 2000 N⋅m, and the flywheel starts from rest. The angular acceleration can be found using the formula α = T/I, where α is the angular acceleration, T is the torque, and I is the moment of inertia. In this case, α = 2000 N⋅m / 580 kg⋅m², which results in α = 3.45 rad/s². Therefore, the correct answer is A) 3.45 rad/s².