Question

The force of magnitude 10 n acting on an object and the object's displacement of magnitude 3 m are perpendicular. what is the work done on the object by the force?

a) 30 J

b) 0 J

c) 5 J

d) 15 J

Answer 1

The work done on an object when a force and the object's displacement are perpendicular is 0 J, because the cosine of 90°, the angle between the force and displacement, is zero.

Step-by-step explanation:

When a force and displacement are perpendicular, the work done is zero. This is because work is calculated using the formula W = F × d × cos(θ), where F is the magnitude of the force, d is the displacement, and θ is the angle between the force and displacement vectors. In this case, since the force of magnitude 10 N is perpendicular to the displacement of 3 m, the angle θ is 90°, and cos(90°) is 0. Therefore, the work done on the object by the force is 0 J.