Question

If the volume of 5.00 m³ of acetylene at 4.00°C and 160 kPa (absolute) is changed to 4.00 m³ at 86.0°F, what is the resulting pressure?

a. 160 kPa
b. 80 kPa
c. 320 kPa
d. 40 kPa

Answer 1

The resulting pressure is 320 kPa.

Step-by-step explanation:

To solve this problem, we can use the combined gas law equation:

(P1 × V1)/ (T1 × R) = (P2 × V2)/(T2 × R)

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Substituting the known values into the equation, we get:

(160 kPa × 5.00 m³)/ (4.00°C + 273) = (P2 × 4.00 m³)/(86.0°F + 459.67)

Simplifying the equation, we find that:

P2 = (160 kPa × 5.00 m³ × (86.0°F + 459.67))/ (4.00 m³ × (4.00°C + 273))

Calculating the equation, we get P2 = 320 kPa.