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If n=25,

(x-bar)=38, and s=10, find the margin of error at a 90% confidence level.
what is it for the 2 decimals for?

User Hdima
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1 Answer

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Final answer:

The margin of error at a 90% confidence level can be calculated using the formula: Margin of Error = Z * (s / sqrt(n)). Substituting the given values into the formula, the margin of error is approximately 3.29.

Step-by-step explanation:

The margin of error at a 90% confidence level can be calculated using the formula:

Margin of Error = Z * (s / sqrt(n))

Where:

  • Z is the z-score corresponding to the desired confidence level (in this case, for a 90% confidence level, Z will be approximately 1.645)
  • s is the standard deviation of the population (in this case, s = 10)
  • n is the sample size (in this case, n = 25)

Substituting the given values into the formula:

Margin of Error = 1.645 * (10 / sqrt(25)) = 1.645 * (10 / 5) = 3.29

Therefore, the margin of error at a 90% confidence level is approximately 3.29.

User Noor
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