Question

How many moles of AgNO₃ are present in 150. ml of a 0.500 M AgNO₃ solution?

a. 0.150 moles
b. 0.300 moles
c. 0.075 moles
d. 0.500 moles

Answer 1

`\huge{ \boxed{0.075 \: moles}}`

Step-by-step explanation:

The number of moles of
`\AgNO_3` can be found by using the formula:

n = c × v

where:

c is the concentration in M , mol/dm³ or mol/L

v is the volume in L or dm³

n is the number of moles.

From the question

c = 0.500 M

v = 150 mL.

The volume has to be converted first into litres since it's in mL.

`1000 \: ml \: = 1 \: l \\ \therefore \: 150 \: ml = (150)/(1000) * 1 \: l \\ = 0.15l`

`\therefore n = 0.5 * 0.15 \\ = 0.075 \: moles`

Answer 2

To find the moles of AgNO₃ in 150 ml of a 0.500 M solution, convert 150 ml to 0.150 L and use the molarity equation, yielding 0.075 moles of AgNO₃, which is option c.

Step-by-step explanation:

To determine the number of moles of AgNO₃ present in 150 ml of a 0.500 M AgNO₃ solution, you would use the equation:

Molarity (M) = Moles of solute (n) / Volume of solution in liters (L)

Rearranging the formula to solve for moles (n) gives:

n = Molarity (M) × Volume of solution in liters (L)

Given that the volume must be in liters, we first convert 150 ml to liters:

150 ml × (1 L / 1000 ml) = 0.150 L

Next, we use the given molarity and the converted volume to calculate the moles of AgNO₃:

n = 0.500 M × 0.150 L = 0.075 mol

Thus, the correct answer is c. 0.075 moles.